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Poles: 32.26 ft/sē Equator: 32.09 ft/sē 45° Latitude: 32.17 ft/sē |
[QUOTE=DrHenley;74487]Because of the different centrifugal force, the gravity at the equator is smaller than that at the poles. So the precise gravitational acceleration is a function of latitude. They just took the gravitational acceleration at 45° Latitude (halfway between the poles and the equator) as the standard. Paris is at 48.86°, New York City is at 40.67°.
Poles: 32.26 ft/sē Equator: 32.09 ft/sē 45° Latitude: 32.17 ft/sē[/QUOTE Excellent, thanks! |
now my Brain hurts:faint:
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Here is how you find the acceleration due to gravity at any particular latitude (at sea level of course): http://www.cotep.org/forum/picture.p...&pictureid=740 g45: 32.17 ft/sē gpoles: 32.26 ft/sē gequator: 32.09 ft/sē π: 3.1415927 |
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well now it makes sense:D |
I love math! is latitude in degrees or radians?
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Found this on Yahoo Answers:
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Way to technical for me!!!:D
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The π/180 part converts degrees to radians. If you have the latitude in radians already, just leave out the π/180 part. |
Gentlemen, we're figuring energy for handgun and rifle bullets, not the Space Shuttle!
As the Good Colonel aptly put it, a few final inch*pounds at this level are unnecessary. It's getting taken way above most pay-grades on here. All I was trying to do was to put a simple yet fairly accurate formula in front of the guys. Nobody on this forum is going to be taking one-mile .416Barrett shots on Terrorists. You guys are making my head spin and I have a math background myself, though evidently not as heavy as some of you. LOL! |
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